[xml] How to create a DTD.

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From: F. David Sacerdoti (fds@cs.ucsd.edu)
Date: Wed Nov 01 2000 - 19:01:11 EST

I recently read some excellent posts by Harry Blundell that explain how
to create an internal DTD for an XML document. I would like to summerize
the steps in this post. My code creates a DTD from scratch, but uses
much of Harry's code for creating one from a text buffer.

First, what we are trying to create. Something like this:

<?xml version="1.0"?>
<!DOCTYPE MyRootTag [
<!ENTITY e1 SYSTEM "/tmp/e1.xml">
<!ENTITY e2 SYSTEM "/tmp/e2.xml">
]>
<MyRootTag>
  <tag>&e1;</tag>
  <tag>&e2;</tag>
</MyRootTag>

-------------------

The code to create it with libxml:

xmlDocPtr doc;
xmlNodePtr tree,root;
xmlDtdPtr dtd;
xmlEntityPtr e;

  // Setup XML document and its DTD
  doc=xmlNewDoc("1.0");

  dtd=xmlNewDtd(doc,"MyRootTag", NULL,NULL);
  doc->intSubset=dtd;
  dtd->parent=doc;
  dtd->doc=doc;
  doc->children=(xmlNodePtr) dtd;

  root=xmlNewDocNode(doc,NULL,"MyRootTag",NULL);
  xmlDocSetRootElement(doc,root);

  e=xmlAddDtdEntity(doc, "e1" XML_EXTERNAL_GENERAL_PARSED_ENTITY, NULL,
       "/tmp/e1.txt","e1");

  // Build the rest of the tree with the 'root' xmlNodePtr.

  xmlDumpFile(FILE, doc)

--------------

I hope this helps others who are looking to create DTDs for their
documents. I am not sure this is the correct way to do it, but it seems
to work for me.

Dave 

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